h^2=61

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Solution for h^2=61 equation:



h^2=61
We move all terms to the left:
h^2-(61)=0
a = 1; b = 0; c = -61;
Δ = b2-4ac
Δ = 02-4·1·(-61)
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{61}}{2*1}=\frac{0-2\sqrt{61}}{2} =-\frac{2\sqrt{61}}{2} =-\sqrt{61} $
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{61}}{2*1}=\frac{0+2\sqrt{61}}{2} =\frac{2\sqrt{61}}{2} =\sqrt{61} $

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